16m^2+8m-8=0

Solution for 16m^2+8m-8=0 equation:

16m^2+8m-8=0

a = 16; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·16·(-8)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*16}=\frac{-32}{32}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*16}=\frac{16}{32}
=1/2
$